Python Program to Check Armstrong Number

Armstrong number is a number whose sum of the n^th power of digits is equal to the number itself. Where n is called the order, which is equal to the number of digits present in the number.

Now you get the understanding of the Armstrong number, so, let's implement in a python program.
I will be discussing three ways to check for Armstrong number.

1. By taking the number as int datatype.
2. By taking the number as string datatype.
3. And by using recursion.

Check Armstrong number by taking the number as int datatype

In this, we have taken the number as int datatype. And then we find the order of the number. And lastly passed the number to the loop to process it digit by digit.

Code:-

# taking input and storing in num variable
num = int(input("Enter a number: "))

# finding order using len() and str() function
order = len(str(num))   
             
# initializing the sum variable by 0
sum = 0                      
# storing the num in temp variable                       
temp = num                  
   
# going through every digit of number store in temp variable                     
while temp > 0:                                     
    n = temp % 10
    temp = temp // 10
    # storing the sum of cube of the digits in sum variable
    sum = sum + pow(n,order)   
           
# checking whether the sum is equal to num or not               
if(sum == num):                 
    # printing the num is an Armstrong number                   
    print(num,"is an Armstrong Number.")          
else:
    # printing the num is not an Armstrong number
    print(num,"is not an Armstrong Number.")

Output:-

In this, we have used the temp variable and initialized to the number because we have to check the sum of the n^th power of digits of the number with the given number, so we cannot manipulate the given number.

Check Armstrong number by taking the number as string datatype

The idea is same as above but the program is a little bit short and also the process.

Code:-

# taking input and storing in num variable
num = input("Enter a number: ")

# finding order using len() function
order = len(num)  

# initializing the sum variable by 0
sum = 0

# going through every digit of number store in num variable   
for i in num:
    # storing the sum of cube of the digits in sum variable
    sum += pow(int(i),order)

# checking whether the sum is equal to num or not
if sum == int(num):
    # printing the num is an Armstrong number 
    print(num,"is an Armstrong Number.")    
else:
    # printing the num is not an Armstrong number
    print(num,"is not an Armstrong Number.")

Output:-

Now let's discuss the last method.

Check Armstrong number by using recursion

In this, we have created a getSum() recursive function which will return the sum of the n^th power of digits of the number. Rest is almost same.

Code:-

# defining the getSum() recursive function
def getSum(num):
    if num == 0:
        # Base case
        return num
    else:
        # Iterative case
        return pow((num%10),order) + getSum(num//10)

# taking input and storing in num variable
num = int(input("Enter a number: "))

# finding order using len() and str() function
order = len(str(num))  

# initializing the sum variable by getting the sum from getSum()
sum = getSum(num)

# checking whether the sum is equal to num or not
if sum == int(num):
    # printing the num is an Armstrong number 
    print(num,"is an Armstrong Number.")    
else:
    # printing the num is not an Armstrong number
    print(num,"is not an Armstrong Number.")

Output:-

Hence, we have discussed all the ways.